(64x^12)^(1/6)

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Solution for (64x^12)^(1/6) equation: 


D( x )

64*x^12 < 0

64*x^12 < 0

64*x^12 < 0

64*x^12 < 0

64*x^12 < 0 // : 64

x^12 < 0/64

x^12 < 0

x belongs to the empty set

x in (-oo:+oo)

(64*x^12)^(1/6) = 0

2*x^2 = 0 // : 2

x^2 = 0

x = 0

x = 0

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